Heat transfer oil heaterCalculation method for heating power selection

1. Special circumstances require calculation:

A、 Calculate the power of the heater or freezer KW=W × △ t × C × S/860 × T

W=weight of mold or cooling water KG

△ t=the temperature difference between the required temperature and the starting temperature.

C=specific heat oil (0.5), steel (0.11), water (1), plastic (0.45~0.55)

T=time to heat up to the desired temperature (hours)

B、 Request the size of the pump

Need to understand the pump flow rate and pressure (head) required by the customer

P (pressure Kg/cm2)=0.1 × H (head M) × α (specific gravity of heat transfer medium, water=1, oil=0.7-0.9)

L (media required flow rate L/min)=Q (mold required heat Kcal/H)/C (media to hot water ratio=1 oil=0.45) × △ t (temperature difference between circulating media entering and leaving the mold) × α × 60

2. Selection of freezer capacity

A. Q (freezing capacity Kcal/H)=Q1+Q2

Q1 (Heat brought into the mold by raw materials Kcal/H)=W (Weight of raw materials injected into the mold per hour KG) × C × (T1-T2) × S (Safety factor 1.5~2) T1 Temperature of raw materials in the material tube; The temperature at which T2 finished products are taken out of the mold; The heat generated by Q2 hot runner is Kcal/H

B、 Quick calculation method (not applicable with hot runner)

1RT=7~8 OZ 1OZ=28.3g (including safety factor)

1RT=3024Kcal/H=12000BTU/H=3.751KW

1KW=860 Kcal/H 1 Kcal=3.97BTU

3. Cooling tower selection=A+B

A、 Used for injection molding machines

Cooling tower RT=Injector horsepower (HP) x 0.75KW x 860Kcal x 0.4 ÷ 3024

B、 Used for refrigerators

Cooling tower RT=Cold ton of freezer (HP) × 1.25